3.88 \(\int \frac{1}{x^4 (a+b \log (c x^n))^3} \, dx\)

Optimal. Leaf size=105 \[ \frac{9 e^{\frac{3 a}{b n}} \left (c x^n\right )^{3/n} \text{Ei}\left (-\frac{3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 b^3 n^3 x^3}+\frac{3}{2 b^2 n^2 x^3 \left (a+b \log \left (c x^n\right )\right )}-\frac{1}{2 b n x^3 \left (a+b \log \left (c x^n\right )\right )^2} \]

[Out]

(9*E^((3*a)/(b*n))*(c*x^n)^(3/n)*ExpIntegralEi[(-3*(a + b*Log[c*x^n]))/(b*n)])/(2*b^3*n^3*x^3) - 1/(2*b*n*x^3*
(a + b*Log[c*x^n])^2) + 3/(2*b^2*n^2*x^3*(a + b*Log[c*x^n]))

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Rubi [A]  time = 0.106838, antiderivative size = 105, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.188, Rules used = {2306, 2310, 2178} \[ \frac{9 e^{\frac{3 a}{b n}} \left (c x^n\right )^{3/n} \text{Ei}\left (-\frac{3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 b^3 n^3 x^3}+\frac{3}{2 b^2 n^2 x^3 \left (a+b \log \left (c x^n\right )\right )}-\frac{1}{2 b n x^3 \left (a+b \log \left (c x^n\right )\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^4*(a + b*Log[c*x^n])^3),x]

[Out]

(9*E^((3*a)/(b*n))*(c*x^n)^(3/n)*ExpIntegralEi[(-3*(a + b*Log[c*x^n]))/(b*n)])/(2*b^3*n^3*x^3) - 1/(2*b*n*x^3*
(a + b*Log[c*x^n])^2) + 3/(2*b^2*n^2*x^3*(a + b*Log[c*x^n]))

Rule 2306

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*Log
[c*x^n])^(p + 1))/(b*d*n*(p + 1)), x] - Dist[(m + 1)/(b*n*(p + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p + 1), x]
, x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1] && LtQ[p, -1]

Rule 2310

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Dist[(d*x)^(m + 1)/(d*n*(c*x^n
)^((m + 1)/n)), Subst[Int[E^(((m + 1)*x)/n)*(a + b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, d, m, n, p}
, x]

Rule 2178

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(F^(g*(e - (c*f)/d))*ExpIntegral
Ei[(f*g*(c + d*x)*Log[F])/d])/d, x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !$UseGamma === True

Rubi steps

\begin{align*} \int \frac{1}{x^4 \left (a+b \log \left (c x^n\right )\right )^3} \, dx &=-\frac{1}{2 b n x^3 \left (a+b \log \left (c x^n\right )\right )^2}-\frac{3 \int \frac{1}{x^4 \left (a+b \log \left (c x^n\right )\right )^2} \, dx}{2 b n}\\ &=-\frac{1}{2 b n x^3 \left (a+b \log \left (c x^n\right )\right )^2}+\frac{3}{2 b^2 n^2 x^3 \left (a+b \log \left (c x^n\right )\right )}+\frac{9 \int \frac{1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx}{2 b^2 n^2}\\ &=-\frac{1}{2 b n x^3 \left (a+b \log \left (c x^n\right )\right )^2}+\frac{3}{2 b^2 n^2 x^3 \left (a+b \log \left (c x^n\right )\right )}+\frac{\left (9 \left (c x^n\right )^{3/n}\right ) \operatorname{Subst}\left (\int \frac{e^{-\frac{3 x}{n}}}{a+b x} \, dx,x,\log \left (c x^n\right )\right )}{2 b^2 n^3 x^3}\\ &=\frac{9 e^{\frac{3 a}{b n}} \left (c x^n\right )^{3/n} \text{Ei}\left (-\frac{3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 b^3 n^3 x^3}-\frac{1}{2 b n x^3 \left (a+b \log \left (c x^n\right )\right )^2}+\frac{3}{2 b^2 n^2 x^3 \left (a+b \log \left (c x^n\right )\right )}\\ \end{align*}

Mathematica [A]  time = 0.114823, size = 89, normalized size = 0.85 \[ \frac{9 e^{\frac{3 a}{b n}} \left (c x^n\right )^{3/n} \text{Ei}\left (-\frac{3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )+\frac{b n \left (3 a+3 b \log \left (c x^n\right )-b n\right )}{\left (a+b \log \left (c x^n\right )\right )^2}}{2 b^3 n^3 x^3} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^4*(a + b*Log[c*x^n])^3),x]

[Out]

(9*E^((3*a)/(b*n))*(c*x^n)^(3/n)*ExpIntegralEi[(-3*(a + b*Log[c*x^n]))/(b*n)] + (b*n*(3*a - b*n + 3*b*Log[c*x^
n]))/(a + b*Log[c*x^n])^2)/(2*b^3*n^3*x^3)

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Maple [F]  time = 0.741, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{4} \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) ^{3}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^4/(a+b*ln(c*x^n))^3,x)

[Out]

int(1/x^4/(a+b*ln(c*x^n))^3,x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{b{\left (n - 3 \, \log \left (c\right )\right )} - 3 \, b \log \left (x^{n}\right ) - 3 \, a}{2 \,{\left (b^{4} n^{2} x^{3} \log \left (x^{n}\right )^{2} + 2 \,{\left (b^{4} n^{2} \log \left (c\right ) + a b^{3} n^{2}\right )} x^{3} \log \left (x^{n}\right ) +{\left (b^{4} n^{2} \log \left (c\right )^{2} + 2 \, a b^{3} n^{2} \log \left (c\right ) + a^{2} b^{2} n^{2}\right )} x^{3}\right )}} + 9 \, \int \frac{1}{2 \,{\left (b^{3} n^{2} x^{4} \log \left (x^{n}\right ) +{\left (b^{3} n^{2} \log \left (c\right ) + a b^{2} n^{2}\right )} x^{4}\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(a+b*log(c*x^n))^3,x, algorithm="maxima")

[Out]

-1/2*(b*(n - 3*log(c)) - 3*b*log(x^n) - 3*a)/(b^4*n^2*x^3*log(x^n)^2 + 2*(b^4*n^2*log(c) + a*b^3*n^2)*x^3*log(
x^n) + (b^4*n^2*log(c)^2 + 2*a*b^3*n^2*log(c) + a^2*b^2*n^2)*x^3) + 9*integrate(1/2/(b^3*n^2*x^4*log(x^n) + (b
^3*n^2*log(c) + a*b^2*n^2)*x^4), x)

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Fricas [B]  time = 0.738719, size = 524, normalized size = 4.99 \begin{align*} \frac{3 \, b^{2} n^{2} \log \left (x\right ) - b^{2} n^{2} + 3 \, b^{2} n \log \left (c\right ) + 3 \, a b n + 9 \,{\left (b^{2} n^{2} x^{3} \log \left (x\right )^{2} + b^{2} x^{3} \log \left (c\right )^{2} + 2 \, a b x^{3} \log \left (c\right ) + a^{2} x^{3} + 2 \,{\left (b^{2} n x^{3} \log \left (c\right ) + a b n x^{3}\right )} \log \left (x\right )\right )} e^{\left (\frac{3 \,{\left (b \log \left (c\right ) + a\right )}}{b n}\right )} \logintegral \left (\frac{e^{\left (-\frac{3 \,{\left (b \log \left (c\right ) + a\right )}}{b n}\right )}}{x^{3}}\right )}{2 \,{\left (b^{5} n^{5} x^{3} \log \left (x\right )^{2} + b^{5} n^{3} x^{3} \log \left (c\right )^{2} + 2 \, a b^{4} n^{3} x^{3} \log \left (c\right ) + a^{2} b^{3} n^{3} x^{3} + 2 \,{\left (b^{5} n^{4} x^{3} \log \left (c\right ) + a b^{4} n^{4} x^{3}\right )} \log \left (x\right )\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(a+b*log(c*x^n))^3,x, algorithm="fricas")

[Out]

1/2*(3*b^2*n^2*log(x) - b^2*n^2 + 3*b^2*n*log(c) + 3*a*b*n + 9*(b^2*n^2*x^3*log(x)^2 + b^2*x^3*log(c)^2 + 2*a*
b*x^3*log(c) + a^2*x^3 + 2*(b^2*n*x^3*log(c) + a*b*n*x^3)*log(x))*e^(3*(b*log(c) + a)/(b*n))*log_integral(e^(-
3*(b*log(c) + a)/(b*n))/x^3))/(b^5*n^5*x^3*log(x)^2 + b^5*n^3*x^3*log(c)^2 + 2*a*b^4*n^3*x^3*log(c) + a^2*b^3*
n^3*x^3 + 2*(b^5*n^4*x^3*log(c) + a*b^4*n^4*x^3)*log(x))

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{x^{4} \left (a + b \log{\left (c x^{n} \right )}\right )^{3}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**4/(a+b*ln(c*x**n))**3,x)

[Out]

Integral(1/(x**4*(a + b*log(c*x**n))**3), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \log \left (c x^{n}\right ) + a\right )}^{3} x^{4}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(a+b*log(c*x^n))^3,x, algorithm="giac")

[Out]

integrate(1/((b*log(c*x^n) + a)^3*x^4), x)